Expanding a single bracket
Brackets
Expanding a single bracket
Expand 4(2x − 5).(2 marks)
Worked solutionIn plain English
In plain EnglishWrite the 4 down the side and the two terms in the bracket, 2x and −5, along the top. Keep the sign with each term.
2Multiply to fill each cell.= 8x − 20✓1Both terms correct✓2
In plain English4 × 2x = 8x and 4 × −5 = −20. Then write the terms out in a line.
⚠ A common mistake: only multiplying the first term: 8x − 5. Every term in the bracket gets multiplied.
Marking pointsM1 8x
M2 −20
Brackets
A letter outside the bracket
Expand a(a + 6).(2 marks)
Worked solutionIn plain English
In plain Englisha × a = a² (a squared). a × 6 = 6a.
2Write it out.= a² + 6a✓2
In plain EnglishWrite the two answers from the grid with a + between them. a² and 6a are not like terms, so this is as simple as it gets.
Marking pointsM1 a²
M2 +6a
Expanding two brackets and collecting like terms
Brackets
Two brackets, then collect like terms
Expand and simplify 3(x + 4) + 2(x − 1).(3 marks)
Worked solutionIn plain English
1Expand the first bracket.3x + 12✓1
In plain English3 × x = 3x and 3 × 4 = 12.
2Expand the second bracket.3x + 12 + 2x − 2✓2
In plain English2 × x = 2x and 2 × −1 = −2. Write all four terms in a line.
3Collect like terms.3x + 2x = 5x x terms12 − 2 = 10 numbers= 5x + 10✓3
In plain EnglishPut the x terms together and the numbers together.
Marking pointsM1 3x + 12
M2 2x − 2
M3 5x + 10
Brackets
Taking a bracket away
Expand and simplify 5(2y + 3) − 2(y + 4).(3 marks)
Worked solutionIn plain English
1First bracket.10y + 15✓1
In plain EnglishMultiply each term in the first bracket by 5: 5 × 2y = 10y and 5 × 3 = 15.
2Second bracket: the − goes with the 2.10y + 15 − 2y − 8✓2
In plain EnglishThe number outside is −2, so −2 × y = −2y and −2 × 4 = −8.
3Collect like terms.10y − 2y = 8y, 15 − 8 = 7= 8y + 7✓3
In plain EnglishPut the y terms together and the numbers together. Be careful with the signs: it is − 2y and − 8.
⚠ A common mistake: writing −2y + 8. The minus belongs to the 2, so it multiplies the 4 as well.
Marking pointsM1 10y + 15
M2 −2y − 8
M3 8y + 7
Factorising: a number outside
Brackets
Factorising with a number
Factorise 6x + 9.(2 marks)
Worked solutionIn plain English
1Find the HCF.Factors of 6: 1, 2, 3, 6Factors of 9: 1, 3, 9HCF = 3✓1
In plain EnglishThe highest number that goes into both 6 and 9 is 3.
2Divide each term by the HCF.6x3 = 2x, 93 = 36x + 9 = 3(2x + 3)✓2Check: 3 × 2x = 6x, 3 × 3 = 9 ✓
In plain EnglishPut the 3 outside the bracket. Inside goes what is left of each term after dividing by 3.
Marking pointsM1 HCF = 3
M2 3(2x + 3)
Brackets
Make sure it is fully factorised
Factorise 12a − 18.(2 marks)
Worked solutionIn plain English
1Find the highest common factor.2, 3 and 6 all go into 12 and 18HCF = 6✓1
In plain EnglishIf you used 2 or 3, there would still be a common factor left inside the bracket.
2Divide each term.12a6 = 2a, 186 = 36(2a − 3)✓2
In plain EnglishDivide each term by 6 to find what goes inside the bracket. Check by expanding: 6 × 2a = 12a and 6 × 3 = 18.
⚠ Not fully factorised: 2(6a − 9) is equal, but 6 and 9 still share a factor of 3. Always use the highest common factor.
Marking pointsM1 HCF = 6
M2 6(2a − 3)
Factorising: a letter outside
Brackets
A letter as the common factor
Factorise x² + 7x.(2 marks)
Worked solutionIn plain English
1Find the common factor.x² = x × x, 7x = 7 × xHCF = x✓1
In plain EnglishBoth terms have an x in them.
2Divide each term by x.x²x = x, 7xx = 7x(x + 7)✓2
In plain EnglishPut x outside and what is left inside. Check by expanding: x × x = x² and x × 7 = 7x.
Marking pointsM1 HCF = x
M2 x(x + 7)
Brackets
A number and a letter
Factorise 8y² + 12y.(2 marks)
Worked solutionIn plain English
1Numbers and letters.HCF of 8 and 12 is 4Both terms have a yHCF = 4y✓1
In plain EnglishTake out the biggest number and the letter that both terms share.
2Divide each term by 4y.8y²4y = 2y, 12y4y = 34y(2y + 3)✓2
In plain EnglishPut 4y outside and what is left inside. Check by expanding: 4y × 2y = 8y² and 4y × 3 = 12y.
Marking pointsM1 HCF = 4y
M2 4y(2y + 3)