Linlithgow Academy · Mathematics · S2 Revision

Tolerance

Calculating limits, writing limits as a tolerance, and deciding whether measurements are acceptable.

Key ideas

What tolerance means

Nothing is made exactly the right size. A tolerance says how far from the target size is still acceptable.

25 ± 0.3 mm

Target 25 mm, allowed to be 0.3 mm over or under.

Limits

Lower limit = target − tolerance

Upper limit = target + tolerance

25 ± 0.3: from 24.7 mm to 25.3 mm

From limits back to tolerance

Target = upper + lower2

Tolerance = upper − lower2

Acceptable?

A measurement is acceptable if it is between the limits (or exactly on one).

Always quote the limits when you explain.

24.72525.3lower limitupper limitmm

Calculating limits

Tolerance

Calculating the limits

A bolt is made to a length of 40 ± 0.5 mm. Find the lower and upper limits.(2 marks)
39.54040.5lower limitupper limitmm
Lower limit: take away.40 − 0.5 = 39.5 mm✓1
In plain EnglishThe bolt can be up to 0.5 mm shorter than 40 mm.
Upper limit: add.40 + 0.5 = 40.5 mm✓2
In plain EnglishThe bolt can be up to 0.5 mm longer than 40 mm.
Marking points
M1 39.5 mm
M2 40.5 mm

From limits to tolerance

Tolerance

Writing limits as a tolerance

The weight of a bag of flour must be between 1.46 kg and 1.54 kg. Write this in the form target ± tolerance.(2 marks)
Find the target: halfway.Target = 1.54 + 1.462 = 32 = 1.5 kg✓1
In plain EnglishThe target is exactly halfway between the limits: add them and halve.
Find the tolerance.Tolerance = 1.54 − 1.462 = 0.082 = 0.04 kg1.5 ± 0.04 kg✓2
In plain EnglishThe gap between the limits is 0.08 kg. Half of that is above the target and half is below, so the tolerance is 0.04 kg.
Marking points
M1 1.5 kg
M2 ± 0.04 kg

Is it acceptable?

Tolerance

Is it acceptable?

A pipe should be 120 ± 2 mm long. A pipe measures 117.5 mm. Is it acceptable? Give a reason.(2 marks)
118120122lower limitupper limitmm117.5
Find the limits.120 − 2 = 118 mm120 + 2 = 122 mm✓1
In plain EnglishWork out the smallest and largest lengths allowed.
Compare and explain.117.5 mm < 118 mm, so it is not acceptable✓2
In plain EnglishQuote the numbers: 117.5 is below the lower limit of 118, so the pipe is too short.
⚠ Marks are lost for just "no". Give the limits and compare them with the measurement.
Marking points
M1 118 and 122
M2 No, 117.5 < 118

Tolerance in context

Tolerance

Quality control

Chocolate bars should weigh 45 ± 1.5 g. Five bars weigh: 44.2 g, 46.8 g, 43.4 g, 45.9 g, 46.5 g. How many bars are acceptable?(2 marks)
Find the limits.45 − 1.5 = 43.5 g45 + 1.5 = 46.5 g✓1
In plain English± 1.5 means the weight can be up to 1.5 g less or 1.5 g more than 45 g. Take away 1.5 for the lowest weight and add 1.5 for the highest.
Check each bar.44.2 ✓, 46.8 ✗ (too heavy), 43.4 ✗ (too light), 45.9 ✓, 46.5 ✓ (on the limit)3 bars are acceptable✓2
In plain EnglishA bar that is exactly on a limit is still acceptable.
Marking points
M1 43.5 and 46.5
M2 3 bars

0 of 0 complete

Your turn

Calculator allowed. When you decide if something is acceptable, check it against both limits. Stuck? Tap Need a hint?